diff --git a/_psets/11.md b/_psets/11.md
index 7c96ce1d3b91ea4b1ccc1c2031cb9ecc1a2ffcd0..f81dbf43d5464d769e7d9457f4714050ab51fa84 100644
--- a/_psets/11.md
+++ b/_psets/11.md
@@ -2,11 +2,13 @@
 title: Problem Set 11
 ---
 
+
 ## (14.1)
 
 {:.question}
 Do a Taylor expansion of equation (14.6) around V = 0.
 
+
 ## (14.2)
 
 {:.question}
@@ -16,12 +18,28 @@ velocity v by $$IV = mgv$$. Using the inverse AC Josephson effect (equation 14.2
 voltage, and the quantum Hall effect (equation 13.41) along with the inverse AC Josephson effect to
 determine the current, relate the measurement to fundamental constant(s).
 
+
 ## (14.3)
 
 {:.question}
 If a SQUID with an area of $$A = 1 cm^2$$ can detect 1 flux quantum, how far away can it sense the
 field from a wire carrying 1 A?
 
+As found in problem 6.4 in [problem set 4](/psets/04.html), the magnitude of the magnetic field a
+distance $$r$$ away from an infinitely long and thin conductor carrying a current $$I$$ is $$I/(2
+\pi r)$$. One flux quantum is $$\num{2.07e-7} \si{G \cdot cm^2}$$ i.e. $$\num{2.07e-11} \si{T \cdot
+cm^2}$$. So to get one flux quantum over $$1 \si{cm^2}$$, we need a magnetic field of
+$$\num{2.07e-11} \si{T}$$. Thus a one amp current can be detected at a distance of
+
+$$
+\begin{align*}
+r &= \frac{\mu_o I}{2 \pi B} \\
+&= \frac{\num{1.26e-6} \si{T m / A} \cdot 1 \si{A}}{2 \pi \cdot \num{2.07e-11} \si{T}} \\
+&= \num{9.66e3} \si{m}
+\end{align*}
+$$
+
+
 ## (14.4)
 
 {:.question}
@@ -29,12 +47,14 @@ Typical parameters for a quartz resonator are $$C_e = 5 \si{pF}$$, $$C_m = 20 \s
 \si{mH}$$, $$R_m = 6 \si{\ohm}$$. Plot, and explain, the dependence of the reactance (imaginary part
 of the impedance), resistance (real part), and the phase angle of the impedance on the frequency.
 
+
 ## (14.5)
 
 {:.question}
 If a ship traveling on the equator uses one of John Harrison’s chronometers to navigate, what is the
 error in its position after one month? What if it uses a cesium beam atomic clock?
 
+
 ## (14.6)
 
 {:.question}