From 0aaa09c4cb63d53d8c20a4071286379f25c5a065 Mon Sep 17 00:00:00 2001
From: Erik Strand <erik.strand@cba.mit.edu>
Date: Thu, 14 Mar 2019 11:20:32 -0400
Subject: [PATCH] Proofing
---
_psets/5.md | 13 +++++++++----
1 file changed, 9 insertions(+), 4 deletions(-)
diff --git a/_psets/5.md b/_psets/5.md
index c8792a4..80d653e 100644
--- a/_psets/5.md
+++ b/_psets/5.md
@@ -172,7 +172,10 @@ mil is a thousandth of an inch), what is the inner diameter?
Solving the formula above for $$r_i$$,
$$
-r_i = r_0 \cdot e^{-2 \pi \cdot 51.6 \sqrt{\epsilon_0 \epsilon_r / \mu_0}}
+\begin{align*}
+r_i &= r_0 \cdot e^{-2 \pi \cdot 51.6 \sqrt{\epsilon_0 \epsilon_r / \mu_0}} \\
+&= 8.2 \si{mils}
+\end{align*}
$$
### (e)
@@ -181,10 +184,12 @@ $$
For RG58/U, at what frequency does the wavelength become comparable to
the diameter?
-We know $$\lambda \nu = c$$, so
-
$$
-\num{2e8} \si{m/s} \cdot \frac{1}{2 \cdot \num{1.48e-3} \si{m}} = \num{6.76e10} \si{Hz}
+\begin{align*}
+\nu &= \frac{c}{\lambda} \\
+&= \frac{\num{2e8} \si{m/s}}{2 \cdot \num{1.48e-3} \si{m}} \\
+&= \num{6.76e10} \si{Hz}
+\end{align*}
$$
--
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